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Velocity vs Time

Page history last edited by Hannah 3 years, 5 months ago
Speed/Velocity Vs. Time

 

 

 

Experiment Questions:

  1. How does the Position/Distance vs. Time graph explain the speed of an object quantitatively?
  2. How does the acceleration of an object affect the slope of the line in a speed/velocity vs. time graph?


 Vocabulary:

  • Speed:
    • The rate at which an object moves
    • Speed only changes when an object speeds up or slows down
      • Speed = Distance ÷ Time
  • Velocity:
    • An objects speed in a specific direction
    • Velocity changes when an object speeds up, slows down, or moves in a different direction
  • Acceleration:
    • the rate at which velocity changes

 


Part 1: Constant Velocity (air puck experiment)

Finding the velocity at each meter: By finding the slope of the line from the Position/Distance vs. Time graph

Slope = Rise ÷ Run

Slope = (y2- y1) ÷ (x2- x1)

 

Use data from the air puck (Position vs. Time): Constant Speed

 

Insert Constant Speed Data Table Here Insert Position vs. Time (constant speed) Graph Here

 

Avg. Time

(sec)

Distance/position (m)

0

0

0.62

1

1.24

2

1.86

3

2.48

4

  1. First, find the "Rise" which in this case is the "DISTANCE" between each tape mark.  SHOW ALL WORK in your science notebook!
  2. Second, find the "Run" which in this case is the "TIME" it takes for the air puck to travel to each tape mark. SHOW ALL WORK in your science notebook!

 

 

Now, calculate the speed and enter it in the table above. You may use a calculator. Round to the nearest hundredth. Show the formula you used below:

 

Velocity = Rise÷Run

At Meter 0:

 


= 0 m/s

Velocity = Rise÷Run

From 0 - 1 meter:

 


= 1.61 m/s

Velocity = Rise÷Run

From 1 - 2 meters:

 


= 1.61 m/s

Velocity = Rise÷Run

From 2 - 3 meters:

 


= 1.61 m/s

Velocity =Rise÷Run

from 3 - 4 meters:

 


= 1.61 m/s

 

Now Calculate the AVERAGE SPEED of the air puck from 0 m to 4 m.

Average Speed = Total Distance ÷ Total Time

 

4m ÷  2.48s

 

= 1.61 m/s

 

 

Velocity vs. Time Data Table (constant speed)

Avg. Time (sec)

Velocity (m/s)

 

0

0

 

0.62 

1.61

 

1.24

1.61

 

 1.86

 1.61

 

2.48

 1.61

 


 


                                    Velocity vs. Time Graph
  • straight line (linear)
  • Constant slope (zero slope)

 

Part 2: Increasing Velocity (metal ball with ramp experiment)

 

Finding the velocity at each meter: By finding the slope of the line from the Position/Distance vs. Time graph

Slope = Rise / Run

Slope = (y2- y1) ÷ (x2- x1)

 

Use data from the ramp and metal ball (Position vs. Time): Speeding Up

Insert Constant Speed Data Table Here

Position vs. Time (constant speed) Graph Here

 

Avg. Time

(sec)

Distance (m)

0

0

1.33

0.75

2.0

1.5

2.6

2.25

3.06

3

  1. First, find the "Rise" which in this case is the "DISTANCE" between each tape mark.  SHOW ALL WORK in your science notebook!
  2. Second, find the "Run" which in this case is the "TIME" it takes for the air puck to travel to each tape mark. SHOW ALL WORK in your science notebook!

 

Now, calculate the speed and enter it in the table above. You may use a calculator. Round to the nearest hundredth. Show the formula you used below:

 

Velocity = Rise÷Run

At Meter 0:

 

 


= 0 m/s

Velocity = Rise÷Run

From 0 - 0.75 meter:

 


= 0.56 m/s

Velocity = Rise÷Run

From 0.75 - 1.5 meters:

 


= 1.12 m/s

Velocity = Rise÷Run

From 1.5 - 2.25 meters:

 


= 1.25 m/s

Velocity =Rise÷Run

from 2.25 - 3 meters:

 


= 1.88 m/s

Calculate the AVERAGE SPEED of the metal ball from 0 m to 3 m.

Average Speed = Total Distance ÷ Total Time

 

3m ÷  3.06s

 

= m/s

 

 

Velocity vs. Time Data Table (Speeding Up)

Avg. Time (sec)

Velocity (m/s)

 

 0

0

 

 1.33

 0.56

 

2

 1.12

 

 2.6

 1.25

 

 3.06

 1.88

 

                               Speed/Velocity vs. Time Graph
  • The slope is always going to be positive

 

 

Part 3: Decreasing Velocity (metal ball on floor experiment)

 

Finding the velocity at each meter: By finding the slope of the line from the Position/Distance vs. Time graph

Slope = Rise / Run

Slope = (y2- y1) ÷ (x2- x1)

 

Use data from the toy car (Position vs. Time): Slowing Down

Insert Constant Speed Data Table Here Insert Position vs. Time (constant speed) Graph Here
 

Avg. Time

(sec)

Distance (m)

0

0

1.0

1

2.15

2

3.47

3

5.12

4

  1. First, find the "Rise" which in this case is the "DISTANCE" between each tape mark.  SHOW ALL WORK in your science notebook!
  2. Second, find the "Run" which in this case is the "TIME" it takes for the air puck to travel to each tape mark. SHOW ALL WORK in your science notebook!

 

Now, calculate the speed and enter it in the table above. You may use a calculator. Round to the nearest hundredth. Show the formula you used below:

 

Velocity = Rise÷Run

At Meter 0:

 


= 0 m/s

Velocity = Rise÷Run

From 0 - 1 meter:

 


= 1 m/s

Velocity = Rise÷Run

From 1 - 2 meters:

 


= 0.86 m/s

Velocity = Rise÷Run

From 2 - 3 meters:

 


= 0.75 m/s

Velocity =Rise÷Run

from 3 - 4 meters:

 


= 0.6 m/s

 

Calculate the AVERAGE Speed of the car from 0 m to 4 m.

Average Speed = Total Distance ÷ Total Time

 

4m ÷ 5.12 s

 

= 0.78 m/s

 

 

Velocity vs. Time Data Table (Slowing Down)

Avg. Time (sec)

Velocity (m/s)

 

 0

0

 

 1

1

 

 2.15

 0.86

 

 3.47

 0.75

 

 5.12

 0.6

 

                                    Insert Velocity vs. Time Graph here
  • Negative Slope
  • Non-Linear

 

 

Part 4: Analyzing Speed vs. Time Graph

Time Range
Is the car Accelerating, Decelerating or not Accelerating?
Is the slope Positive, Negative, or Zero Slope?
0 to 1 sec
Accelerating Positive Slope

 

1 to 2 sec
Not Accelerating

 

Zero Slope

 

2 to 3 sec
Accelerating Positive Slope

 

3 to 6 sec

Decelerating

Negative Slope

 

Time Range
Is the car Accelerating, Decelerating or not Accelerating?
Is the slope Positive, Negative, or Zero Slope?
0 to 5 hours
Accelerating Positive Slope
5 to 10 hours
Accelerating

Positive Slope

10 to 15 hours
Not Accelerating Zero Slope
15 to 20 hours
Decelerating Negative Slope
20 to 25 hours Accelerating Positive Slope
25 to 30 hours Decelerating Zero Slope

Part 5: Calculating Average Speed

  • Speed = Distance ÷ Time
  • Show ALL of your work!!

1.    A car travels 300 miles in 6 hours.  What is the average speed of the car?

300/6= 50.    Average speed= 5o miles/hr.
 

2.    You ride your bike to your friend’s house.  You know that he lives 2500 meters away because you were bored one day and measured it.  It took you 10 minutes to get there.  What was your average speed on the bike?

S=d/t       S= 2500/10 =  250      Speed= 250 meters/m

3.    You are at home and dying for a slurpee so you walk to 7-11 to get one.  It’s 2000 feet away.  After walking 4 minutes you meet up with friends and talk for 3 minutes.  Your friends then join you and it takes you another 5 minutes to get to 7-11.  What is your average speed for you to go from your house to 7-11?     s=d/t       S= 2000/9 =  222.2      Speed= 222.2ft/min.

 

4. Fill in the data table

  • You will need to rearrange the equation Speed = Distance / Time to find the missing information
  • SHOW ALL WORK IN YOUR SCIENCE NOTEBOOK!
Speed
Distance
Time
60 mph 30 miles .5hr
78 m/s 112 meters 1.4s
220 ft/min 3300ft 15 min
32 cm/s 3136cm 98 sec

Part 6: Summary

Summary

         No experiment this time. We used the results from our air puck experiment, and the metal ball and ramp experiment to create two different graphs. We then used our information to calculate the Average Speed of each experiment. We ended up making 2 different graphs, a Position vs Time graph and a Speed vs Time graph. In a position vs time graph the slope will always turn out positive, until the object comes to a stop (then it'll be at a zero slope). When an object remains to move at a constant speed the slope will continue to look the exact same. When an object speeds up the slope will increase and the line will point more upwards (steeper line). And when an object slows down the line starts to decrease.

        When an object increases in acceleration it will show on the graph by making the slope (line) increase in steepness (become more steep). If an object decreases in acceleration, it is shown on the graph as having the  slope (line) become less steep. Last but not leaste if the object continues at the same pace in acceleration it is represented on the graph by continueing to look the same (slope stays the same, doesn't decrease in steepness or increase in steepness).

 

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